Question

A body moving with an initial velocity of 36km/hr of 36km/hr acceleration uniformly at the rate of 4m/s2 from 15 sec. Calculate thetotal distance travelled in 20 sec and final velocity?

Answer 1

Hey

u = 36 km/hr = 10m/s
a = 4m/s2
t=15s
$a = \frac{v - u}{t}$
$4 = \frac{v - 10}{15}$

4×15=v-10
60=v-10
60+10=v
70m/s=v

Now
$s = ut + \frac{1}{2} a {t}^{2} \\ s = 10 \times 15 + \frac{1}{2} \times 4 \times {15}^{2} \\ s = 150 + 2 \times 225 \\ s = 150 + 450 \\ s = 600m$