Question

differentiation of log(3x^2+1)

Answer 1

Hey !!!

Differentiation of log ( 3x² + 2 )

dy/dx = d {log(3x² + 2) } /dx

1st of all differentiate inner part ( 3x² + 1 )

dy/dx = d (3x² + 1 )/dy

=>(2× 3x )

dy/dx= 6x ------1)

after all differentiate

log ( 3x² + 1 )

let 3x² + 1 = x

dy /dx = d ( log ( 3x² + 1 ) /dx

=> d logx /dx

=> 1/x

hence, dy/dx = 1/(3x² + 1 ) ----2)

now multiply 1st and 2nd we get

6x / ( 3x² + 1 ) Answer ✔ /

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Hope it helps you !!!

@Rajukumar111
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