Question

A body moving with an initial velocity of 5M/s accelerates at 2ms-2 . its velocity after 10s is

Answer 1

Answer:

initial velocity, u = 5 m/s acceleration, a = 2 m/s ^ 2

we have to find velocity after 10sec,

you know about kinetic equation of linear motion ? v=u + at,is a Kinetic equation for linear motion. where, v is velocity after t time, u is intial velocity and a is acceleration.

here, u 5m/s, a = 2 m/s and t = 10sec

v = 5 + 2 * 10 = 25 m/s

Explanation:

Hope it helps you

Answer 2

Provided that:

• Initial velocity = 5 mps
• Acceleration = 2 mps sq.
• Time = 10 seconds

To calculate:

• Final velocity

Solution:

• Final velocity = 25 mps $\:$

Using concept(s):

• We can use either first equation of motion or acceleration formula to solve this question!

Using formulas:

• First equation of motion:

• v = u + at

• Acceleration formula:

• a = (v-u)/t

Where, a denotes acceleration, u denotes initial velocity, v denotes final velocity and t denotes time taken.

Required solution:

~ By using first equation of motion!

→ v = u + at

→ v = 5 + 2(10)

→ v = 5 + 20

→ v = 25 mps

→ Final velocity = 25 mps

~ By using acceleration formula!

→ a = (v-u)/t

→ 2 = (v-5)/10

→ 2 × 10 = v - 5

→ 20 = v - 5

→ 20 + 5 = v

→ v = 25 mps

→ Final velocity = 25 mps