a body moving with initial velocity of 5m/s accelerates at 2m/s . it's velocity after 10 sec is
Answers
Answered by
25
hey!
the answer:-
u=5m/s
a=2m/s^2
time=10 seconds.
v=u+at
=5+2×10
5+20
=25m/s
hope this helps!
You may mark as brainliest ✌☺
the answer:-
u=5m/s
a=2m/s^2
time=10 seconds.
v=u+at
=5+2×10
5+20
=25m/s
hope this helps!
You may mark as brainliest ✌☺
Answered by
10
Hi friend here is your answer
_______________________________________
Given
Initial velocity (u) = 5 m/s
Acceleration (a) = 2 m/s square
Time (t) = 10 sec
So by kinematical equation
v = u + at
Substituting the given values
v = 5 + (2)(10)
= 5 + 20
= 25 m/s
So the final velocity means the velocity after 10 sec will be 25 m/s
_______________________________________
Hope it helps you........!!
#TheUsos
Down since
Day One Ish
_______________________________________
Given
Initial velocity (u) = 5 m/s
Acceleration (a) = 2 m/s square
Time (t) = 10 sec
So by kinematical equation
v = u + at
Substituting the given values
v = 5 + (2)(10)
= 5 + 20
= 25 m/s
So the final velocity means the velocity after 10 sec will be 25 m/s
_______________________________________
Hope it helps you........!!
#TheUsos
Down since
Day One Ish
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