Question

a body moving with initial velocity of 6m/s accelerates at 2m/s2 it's velocity after 10sec will be
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Answer 1

Vf2 = Vi2 + 2aΔd

d = VΔt

Δd

=

(Vf + Vi) Δt

2

use this formula it may help u..

Answer 2

Answer:

• Final velocity is 26 m/s.

Given:

• Initial velocity = 6 m/s
• Acceleration = 2 m/s²
• Time taken = 10 sec

Explanation:

$\rule{300}{1.5}$

We are given that a body moving with initial velocity of 6 m/s accelerates at the rate of 2 m/s². We are asked to find out it's final velocity after 10 sec.

From first kinematic equation we know,

$\longrightarrow{\sf{v\ =\ u\ +\ at}}$

Here,

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time taken

Substitute the values,

$\longrightarrow{\sf{v\ =\ 6\ +\ 2 \times 10}} \\ \\ \\ \longrightarrow{\sf{v\ =\ 6\ +\ 20}} \\ \\ \\ \longrightarrow{\sf{v\ =\ 26\ m/s}}$

∴ The final velocity of the body is 26 m/s.

$\rule{300}{1.5}$