Physics, asked by shankarganiger228, 1 year ago

A body moving with the velocity of 20 metre per second is brought to rest with uniform retardation in 4 seconds calculate the retardation and the distance travelled by the body before coming to rest​

Answers

Answered by adarshrajsingh
7

Answer:

The retardation is 5 meter per second square and the distance travelled by the moving body is 120 meter .

Explanation:

Given , u=20m/s , t=4s ,v=0m/s

using 1 equation of motion we have ,

v=u+at

that gives us retardation =5 m/s.square

and the using 2 eqn. of motion .

s=ut+1/2atsquare

we get ,

Distance = 120m

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