A body moving with uniform acceleration has a velocity of -11 centimetre per second when X coordinateis 3 CM if its x-coordinate 2 second later is minus 5 cm what is the magnitude in centimetre per second square of its acceleration
Answers
Answered by
1
the velocity of a particle moving on a x axis is given by v=x^2+x where v is in m/s and x is in m.find its acceleration in m/s^2when passing through point x=2m
anuragkumar75:
firstly differenciate it and then put the value of x in it. after differentiating you will get 2x+1 and eventually you answer will be 5m/s^2
sorry
that was wrong
as we know that acceleration =v.dv/dx =(x^2+x)(2x+1)=6×5=30m/sec^2
Similar questions