Question

A body moving with uniform acceleration travel distance 9 m in 3 s .its initial velocity is 0.then find out displacement after 5 second.​

Answer 1

Given,
Distance =9m
T1=3s
Initial Velocity=0m/s
T2=5s

Final Velocity=?
v=d/t
=9/3
v=3m/s

Acceleration = v-u/t
3-0/3
=1m/s^2

Displacement after 5s
S=ut+1/2at^2
S=u we will write as 3m/s we know it is the final Velocity for the first case but now it is the initial Velocity for the second case
S=3x5+1/2x1x25
S=15+12.5
S=27.5m