Question

A body moving with uniform acceleration
travels 84 m in the first 6 s and 180 m in the
next 5 s. Find : (a) the initial velocity, and (b) the
acceleration of the body.

plz send this answer with procedure as soon as possible. The first right answer will be marked as the brainliest by me.​

Answer 1

Answer :-

Given

• Distance traveled in first 6 sec = 84 m

• Distance traveled in Next 5 sec = 180 m

Now from

S = ut + 1/2 ×at²

For first 6 sec

→84 = u(6) + 1/2× a ×6²

→84 = 6u + 18a

→ 14 = u + 3a ...(i)

For next 5 sec

• Time = 6 + 5

= 11 sec

• Distance = 84 + 180

= 264 m

Then

→ 264 = u(11) + 1/2 × a × 11²

→ 264 = 11u + 121/2 × a

→ 24 = u + 11/2 × a

→ 24 = u + 5.5 a ...(ii)

Now from (ii) - (i)

24 = u + 5.5 a

-(14 = u + 3a)

____________________

10 = 2.5 a

Or

a = 10 ÷ 2.5

a = 4 m/s²

Now from (i)

→14 = u + 3a

→ 14 = u + 12

→ 2 = u

or initial velocity = 2 m/s

So

(a) Initial Velocity = 2 m/s

(b) Acceleration = 4 m/s²