A body moving with uniform acceleration
travels 84 m in the first 6 s and 180 m in the
next 5 s. Find : (a) the initial velocity, and (b) the
acceleration of the body.
plz send this answer with procedure as soon as possible. The first right answer will be marked as the brainliest by me.
Answers
Answered by
11
Answer :-
Given
• Distance traveled in first 6 sec = 84 m
• Distance traveled in Next 5 sec = 180 m
Now from
S = ut + 1/2 ×at²
For first 6 sec
→84 = u(6) + 1/2× a ×6²
→84 = 6u + 18a
→ 14 = u + 3a ...(i)
For next 5 sec
• Time = 6 + 5
= 11 sec
• Distance = 84 + 180
= 264 m
Then
→ 264 = u(11) + 1/2 × a × 11²
→ 264 = 11u + 121/2 × a
→ 24 = u + 11/2 × a
→ 24 = u + 5.5 a ...(ii)
Now from (ii) - (i)
24 = u + 5.5 a
-(14 = u + 3a)
____________________
10 = 2.5 a
Or
a = 10 ÷ 2.5
a = 4 m/s²
Now from (i)
→14 = u + 3a
→ 14 = u + 12
→ 2 = u
or initial velocity = 2 m/s
So
(a) Initial Velocity = 2 m/s
(b) Acceleration = 4 m/s²
Similar questions