Question

A body moving with uniform retardation covers 3 kilometre before his speed reduced to half of its initial value coming to rest in at the distance of

Answer 1

ram ram ...

First, let’s find retardation

a = (v² - u²)/(2S)

= (u²/4 - u²)/(2 × 3)

= -(3u²/4) / 6

= -u²/8

Total distance it covers from starting point is

D = (v² - u²) / (2a)

= (0² - u²) / (2 × (-u²/8))

= 4 km

∴ Extra distance it should travel = 4 km - 3 km = 1 km