Question

The radius of a cylinder is doubled and irs height remaining same. What will happen to its volume

Answer 1

Let the radius be (r) m and Height be (1) m.

Then its volume = πr²h
= 22r²/7

Again, After doubling the radius, The radius would become 2r.

Now,
Its volume = πr²h
= 22/7 × 4r²
= 88r²/7

Hence,
Change in volumes = 88r²/7 ÷ 22r²/7

$\frac{88 {r}^{2} }{7} \times \frac{7}{ 22{r}^{2} }$
= 4

Therefore,
We conclude that the volume will increase 4 times than the older volume if its radius is doubled.










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