The perimeter of a square is 48 CM the area rectangle is 4 cm less then the area of square if the length of the rectangle is 4 cm greater than its breadth find the perimeter of the rectangle
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the perimeter of square is 48 is 4a, a=12
the area of rectangle is lb = 4
4{4+b}= 4
4+b=1
b=-3
perimeter of rectangle is 2{l+b}=
2{4-3}
= 2
the area of rectangle is lb = 4
4{4+b}= 4
4+b=1
b=-3
perimeter of rectangle is 2{l+b}=
2{4-3}
= 2
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