Question

A body moving with velocity of 50 M per second undergoes information of 20m per second square how far is it move in 4 second and what is its velocity after that time​

Answer 1

may...... be..... helpful

Answer 2

Correct Question:

A body moving with velocity of 50m/s undergoes a uniform, acceleration of 20 m/${s}^{2}$. How far does it move in 4 second and what is its velocity

after that time?

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Given:

• Initial velocity= u = 50m/s
• Time = t= 4s
• Acceleration= a = 20 m/${s}^{2}$

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Need to find :

• Final velocity = v=?

• Distance travelled = s=?

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Solution :

From 1st equation of motion we know,

v = u + at

$\implies \: v = 50 + 20 \times 4$

$\implies \: v = 50 + 80 m/s$

$\red{\bold{\boxed{\boxed{ \implies \: v = 130m/s}}}}$

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From 2nd equation of motion we know,

$s = ut + \dfrac{1}{2}a {t}^{2}$

$\implies \: s = 50 \times 4 + \dfrac{1}{2} \times 20 \times {4}^{2} m$

$\implies \: 200 + 160m$

$\red{\bold{\boxed{\boxed{ \implies \: s = 360cm}}}}$