Question

if 2^x=3^y=6^z hence find 1/X+1/y+1/z​

Answer 1

Answer:

Step-by-step explanation:

2^x=3^y=6^z

by k method

2=k^1/x

3=k^1/y

6=k^1/z

we know , 6=2×3

given the values of 2 ,3and 6

k^1/z=k^1/y×k^1/x

same base but different power .so the power will be added.

k^1/z=k^1/y+1/x

cut k by k

1/z=1/y+1/x

taking 1/z to rhs

1/z+1/y+1/x =0