A body of 0.25 kg executes SHM given by m. Calculate the amplitude, angular
frequency, maximum velocity and maximum acceleration.
Answers
Answered by
1
Answer:
The equation of motion of S.H.M x=0.5cos(100+
4
3π
). Comparing it with general equation motion of S.H.M, described as follows, we get, x=Acos(ωt+θ)
(1) Frequency=
2π
ω
, Where ω=100
=
2π
100
=(50π)Hz
(2)Initial phaseϕ=
4
3π
(3)Amplitude A=0.5cm
Maximum velocity=ωA=100×0.5=500m/s
(4)Maximum acceleration=ω
2
A=100
2
×0.5=50m/s
2
(5)Total energy=
2
1
mω
2
A
2
(Mass of the particle=0.1kg)
=
2
1
×0.1×(100)
2
×(0.5)
2
=125J
Similar questions