A body of 0.25kg executes SHM given by y=0.4sin 0.5πt m. Calculate the amplitude, angular frequency, maximum velocity and maximum acceleration
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Answer:
9.8 m/s²
Explanation:
v = Aw = 4*0.5π = 6.28 m/s
a= Aw² = 0.25*π²*4 = 9.8 m/s²
Amplitude=4m
Angular frequency= 0.5π rad/s
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