Question

A body of 0.25kg executes SHM given by y=0.4sin 0.5πt m. Calculate the amplitude, angular frequency, maximum velocity and maximum acceleration​

Answer 1

Answer:

9.8 m/s²

Explanation:

v = Aw = 4*0.5π = 6.28 m/s

a= Aw² = 0.25*π²*4 = 9.8 m/s²

Amplitude=4m

Angular frequency= 0.5π rad/s