Question

A body of 10kg is acted by a force of 129.4n.The acceleration of block is 10m/s^2.The coefficient of kinetic friction is

Answer 1

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Answer 2

Answer:

F+UN=129.4

where

N=mg

u=cocfficient of kinetic friction

ma+mgu=129.4

10+10u=129.4/10

u=(129.4/100) -1

u=29.4/100

u=0.294