Question

A body of 2 kg is initially at rest. If a constant
force of 5 N acts on it for 10 seconds, then
what will be the average power of the force ?
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Answer 1

Answer:

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Explanation:

m=2kg , F=5N. ,t=10s. u=0

$f = ma \\ a = \frac{f}{m } \\ = \frac{5}{2} = 2.5 \\ \\ s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 \times t + \frac{1}{2} \times 2.5 \times {10}^{2} \\ = 0.5 \times 2.5 \times 100 \\ = 125m \\ \\ power = \frac{work \: done}{time} \\ = \frac{f \times s}{t} \\ = \frac{5 \times 125}{10} \\ = 62.5watt$