A body of 2 kg thrown upwards, reaches a maximum height of 5m calculate the work done by the force of gravity during the vertical displacement
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Question :-
A body of 2 kg thrown upwards, reaches a maximum height of 5m calculate the work done by the force of gravity during the vertical displacement .
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Answer :-
Work done = potential energy in the height given ..
Work done = m g h
Given :
m = 2 kg
h = 5 m
g = 9.8 m/s²
Work = m g h
= 2 kg × 9.8 m/s² × 5 m
= 10 kg m × 9.8 m/s²
= 98 kg m²/s²
= 98 J
ANSWER :
The work done is 98 J
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