Question

A body, of 5 kg, hangs at rest from a string wrapped around a wheel of diameter 0.10 m
The torque about the axis of wheel is
(A) 4 N-m
(B) 5.45 N-m (C) 1 N-m
(D) 2.45 N-m​

Answer 1

Answer:

1n-m

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Explanation:

Answer 2

The correct option is (D) 2.45 N-m​.

To find,

The torque about the axis of the wheel.

Given,

A body, of 5 kg, hangs at rest from a string wrapped around a wheel of diameter 0.10 m.

Solution,

The torque, τ, about the axis of the wheel is given by the equation:

τ = Fr,

where F is the force applied perpendicular to the radius of the wheel and r is the radius of the wheel.

In this problem, the weight of the body hanging from the string is the force applied perpendicular to the radius of the wheel. The weight, W, is given by:

W = mg,

where m is the mass of the body and g is the acceleration due to gravity.

Substituting the values given in the problem, we get:

W = 5 kg × 9.81 m/s² = 49.05 N

The radius of the wheel is half of its diameter, so r = 0.05 m.

Therefore, the torque about the axis of the wheel is:

τ = Fr = W × r = 49.05 N × 0.05 m = 2.45 N-m

So the answer is (D) 2.45 N-m.

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