A body of 6000gm has momentum of 180Kg m/s find ,kinetic energy of the body
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Here M=6kg
and P=180kgm/s....so we know that p=MV so
180=6×x by solving we will get x=30m/s and now by using the formula of K.E i.e 1/2mv^2 we will get that k.e is 2700j.
and P=180kgm/s....so we know that p=MV so
180=6×x by solving we will get x=30m/s and now by using the formula of K.E i.e 1/2mv^2 we will get that k.e is 2700j.
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Kinetic energy (K.E) and momentum (p) are related as
K.E = p² / (2m)
So,
K.E = (180 kgm/s)² / (2 × 6 kg)
= 2700 Joules
= 2.7 kJ
Kinetic energy of body is 2.7 kJ
K.E = p² / (2m)
So,
K.E = (180 kgm/s)² / (2 × 6 kg)
= 2700 Joules
= 2.7 kJ
Kinetic energy of body is 2.7 kJ
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