A body of 7300 troops is formed battalion, so that 1/2 of first, 2 /3 of second, 3/4 of third and 4 /5 Of the fourth are all composed of the same number of men, many men were there in each?
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Step-by-step explanation:
Let a, b, c and d be number of men in the four groups.
Then a/2 = 2b/3 = 3c/4 = 4d/5 = x (say)
Then a= 2x, b = 3x/2, c = 4x/3, d= 5x/4
Now a+b+c+d = 7300
=> 2x + 3x/2 + 4x/3 + 5x/4 = 7300
=> 24x + 18x + 16x + 15x = (7300)(12)
=> 73x = 7300(12)
x = 1200
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