Question

A body of M.I. 5 kgm^2 rotating with an angular velocity 6 rad/sec has the same K.E as a mass of 20 kg moving with a velocity of *
1 point
5 m/s
4 m/s
3 m/s
2 m/s​

Answer 1

Answer:

Explanation:

kinetic energy of rotating body =1/2 Iω²

                                                    = 1/2 * 5 * 6 * 6

                                                    = 90 J

velocity of body moving with same kinetic energy

        = 1/2 mv² = 90

        = v² = (90*2) / m

           v² = 180/20 = 9

           v = 3 m/s