A body of mas 1.5kg is thrown vertically upwards with an initial velocity of 15m/s what will be its potential energy at the end of 2sec
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u = 15 m/s
g = 9.8 m/s²
t = 2s
h = ut - 0.5gt²
⇒ h = 15×2 - 0.5×9.8×2²
⇒ h = 30 - 19.6
⇒ h = 10.4m
Potential Energy = mgh = 1.5×9.8×10.4 = 152.88 J
g = 9.8 m/s²
t = 2s
h = ut - 0.5gt²
⇒ h = 15×2 - 0.5×9.8×2²
⇒ h = 30 - 19.6
⇒ h = 10.4m
Potential Energy = mgh = 1.5×9.8×10.4 = 152.88 J
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Initial velocity (u) = 15 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time taken (t) = 2s
Height (h) = ?
h = ut - 0.5 gt²
⇒ h = 15×2 - 0.5×9.8×2²
⇒ h = 30 - 19.6
⇒ h = 10.4m
Potential Energy (PE) = mgh = 1.5×9.8×10.4 = 152.88 J
Acceleration due to gravity (g) = 9.8 m/s²
Time taken (t) = 2s
Height (h) = ?
h = ut - 0.5 gt²
⇒ h = 15×2 - 0.5×9.8×2²
⇒ h = 30 - 19.6
⇒ h = 10.4m
Potential Energy (PE) = mgh = 1.5×9.8×10.4 = 152.88 J
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