a body of mass 0.05 kg is observed to fall with constant velocity the opposite force offer on the body is
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Answered by
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the opposite force offered by the air on the body is :. here
a=9. 8
And mass=0. 05
so the air resistence offered on its surface is
A×M=9. 8×0. 05
" " =0. 49N
a=9. 8
And mass=0. 05
so the air resistence offered on its surface is
A×M=9. 8×0. 05
" " =0. 49N
Answered by
1
The opposite force offers on the body is = 0.05 ×9.8
=0.49 N
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