Question

a body of mass 0.1 kg is dropped from height of 10m. find the kinetic energy of the body just before it strikes the ground

Answer 1

Answer:

K.E=10J

Explanation:

Here, by conservation of energy, the potential energy  of the body at height h is converted into kinetic energy before its strikes the ground.  

Thus, mgh=KE

or KE=0.1(10)10=10J

Answer 2

The Kinetic energy of the body just before it strikes the ground is 9.8 Joules.

Given,

Mass = 0.1 kg

Height = 10 m

To Find,

The kinetic energy of the body just before it strikes the ground

Solution,

During the impact, the body's potential energy at height h is converted into kinetic energy by the conservation of energy.

Therefore, we can say that -

From Conservation of energy,

KE = PE (just before the body strikes the ground)

KE = mgh

where 'm' is the mass of the body

'g' is the acceleration due to gravity

and 'h' is the height

KE = 0.1 x 9.8 x 10

KE = 9.8 J

Hence, we get the kinetic energy as 9.8 J.

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