A body of mass 0.25 kg moving with the velocity 12m/s is stopped by applying a force of 0.6n . Calculate the time taken to stop the body , also calculate the impulse of this force
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6
Answer:
time=5 sec
and impulse = 3 kgm/s in opposite direction of motion.
Explanation:
When it stops the final velocity is zero so apply v=u+at(u=12m/s,v=0),
Also impulse=mv-mu(that is change in momentum).
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Answer:
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