Question

A body of mass 0.4kg is whirled in a horizontal circle of radius 2m with a constant speed of 10m/s calculate its (1) angular speed (2) frequency of revolution (3) time period (4) centripetal acceleration

Answer 1

Answer:

The angular speed is 5 rad/sec,frequency of revolution is 0.8 revolution/sec, time period  1.25 Sec , centripetal acceleration is 5.06 m/s^2

Explanation:

According to the problem the mass , m of the body is 0.4 kg

The radius ,r of the circle is 2 m and the speed, v of the body is 10 m/s

Let angular velocity =ω

Therefore, v = rω

ω= v/r = 10/2 = 5 rad/sec

Now we know,

ω= 2πf [ where f is the frequency]

f= ω/2π = 5/2 x 22/7 = 0.8 revolution/sec

We know time period T can be calculated by 1/f= 1/0.8 = 1.25 Sec

Now to find centripetal acceleration a

a = rω^2 = r x (2πf )^2 = 2 x 4 x (22/7)^2 x (0.8)^2=  5.06 m/s^2

Answer 2

Explanation:

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