Physics, asked by ARUNACHALASHIVA, 10 months ago


A body of mass 0.5 kg experience a force
F = (2 + 3x2) N where x (in metre) is the
displacement from origin. It is released to move
along x-axis from origin then its initial acceleration
is
(1) 2 m/s2
(3) 4 m/s2
(2) 10 m/s2
(4) Zero

Answers

Answered by Anonymous
10

Explanation:

F=ma

a=F/m

a=(2+3*2)/0.5

a=8/0.5

a=4m/s²

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Answered by atharv718393
0

Answer:

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