A body of mass 0.5 kg experience a force
F = (2 + 3x2) N where x (in metre) is the
displacement from origin. It is released to move
along x-axis from origin then its initial acceleration
is
(1) 2 m/s2
(3) 4 m/s2
(2) 10 m/s2
(4) Zero
Answers
Answered by
10
Explanation:
F=ma
a=F/m
a=(2+3*2)/0.5
a=8/0.5
a=4m/s²
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