Question

À body of mass 0.5kg travels in a straight line with velocity v=axraised to 3/2 where a is 5m-1/2s-1. What is work done during displacement from x=0 to x=2m

Answer 1

Answer =

work done -50J

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Explanation in brief->

$\huge{\underline{\sf{\red{Given}}}}$

Velocity of body $v = ax^{3/2}$ here a = 5

Initial velocity of body  $v_i = |_{x=0} = 5 \times 0 = 5 m/s$

Final velocity of body  $v_f |_{x=2} = 5 \times 2^{3/2} = 10 \sqrt{2} m/s$

Find= Work done-??

$\huge\underline{\overline{\mid{\bold{\orange{Solution-}}\mid}}}$

From work energy theorem, we know the formula

$\boxed{W= \dfrac{1}{2} mv_f ^2 - \dfrac{1}{2} m v_i^2}$

Putting all the given values in the formula we get,

$W= \dfrac{1}{2} \times 0.5 \times 10 \sqrt{2} - \dfrac{1}{2} \times 0.5 \times 0$

$W= 50J$

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