A body of mass 0.5kg undergoes a change of velocity of 4cm/s in 4s. What is the force acting on it?
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Answered by
3
f=ma
f=0.5×4/4
f= 0.5× 1 cm/sec
f=0.5 N
f=0.5×4/4
f= 0.5× 1 cm/sec
f=0.5 N
Answered by
5
a = v -u/t
a =400/4
a =100m/s^2
forse =mass × acceleration
f = ma
f = o.5 ×100
50 n is the answer
a =400/4
a =100m/s^2
forse =mass × acceleration
f = ma
f = o.5 ×100
50 n is the answer
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