A body of mass 0.8 kg is moving with initial velocity (4i+3k)m/s which changes into (-6i+2k)m/s. Calculate change in K.E.
Answers
Answered by
0
Answer:
Answer: Initial kinetic energy=1/2mass×magnitude of initial velocity
=1/2×0.8×5=2J. (|u|=√4×4+3×3 =√5)
final kinetic energy=1/2×m×v=1/2×0.8×40=16J. (|v|=√6×6+2×2=√40)
change in kinetic energy=final-initial=16-2=14J
Explanation:
Similar questions