A body of mass 1.5kg is moving with velocity of 10m/s encounter another body of mass 2.5kg moving in opp direction with a velocity of 16m/s n they stick to each other wht is the velocity of the combination
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Answer:
15.71 m/s
Explanation:
M1 equals to 1.5 kg and u1 equals to 10 M per second
M2 equals to 2.5 kg and u 2 equals to 16 m per second
they stick to each other means the velocity will be v now by the formula of law of conservation of momentum v equals to
m1u1+m2u2=m1v1+m2v2
1.5 * 10 + 2.5 * 16 = 1.5 v + 2.5 v
15+40=3.5v
55=3.5v
15.71 m/s
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