A body of mass 1.5kg moving with a velocity of 10m/s encounters another body of mass 2.5 kg moving in opposite direction with a velocity of of 16m/s and they stick to each other. What is the velocity of the combination
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M1 equals to 1.5 kg and u1 equals to 10 M per second
M2 equals to 2.5 kg and u 2 equals to 16 m per second
they stick to each other means the velocity will be v now by the formula of law of conservation of momentum v equals to
m1u1+m2u2=m1v1+m2v2
1.5 * 10 + 2.5 * 16 = 1.5 v + 2.5 v
15+40=3.5v
55=3.5v
15.71 m/s
M2 equals to 2.5 kg and u 2 equals to 16 m per second
they stick to each other means the velocity will be v now by the formula of law of conservation of momentum v equals to
m1u1+m2u2=m1v1+m2v2
1.5 * 10 + 2.5 * 16 = 1.5 v + 2.5 v
15+40=3.5v
55=3.5v
15.71 m/s
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2
Answer:15.71 m/s
Explanation:
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