a body of mass 1 kg dropped from a height of 20 m after 2 sec its postential energy in joules
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m=1kg
t=2s
distance travelled in 2 sec s=ut+1/2at^2
u=0 a= 9.8m/s^2
so , s = ut+1/2at^2
s= 1/2×9.8×2×2
=19.6m
distance between object and earth is 20-19.6=0.4
potential energy= mgh
1×0.4×9.8=3.92J
t=2s
distance travelled in 2 sec s=ut+1/2at^2
u=0 a= 9.8m/s^2
so , s = ut+1/2at^2
s= 1/2×9.8×2×2
=19.6m
distance between object and earth is 20-19.6=0.4
potential energy= mgh
1×0.4×9.8=3.92J
vicky228:
thnx
but the options given are a)3.92 , b)39.2 , c)392 and d)3920
send me the correct option bro
i hope its correct now sorry for inconvenience
ok thnx
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