Question

A body of mass 1 kg exceuting shm whose displacement given by 10(sin60t+π×6) what are kinetic and potential energy after π/2sec

Answer 1

Answer:

Explanation:

x=10sin(60 t + 6pi)

v=600cos(60t+6pi)

v=600cos(60t)

therefore kinetic energy

1/2 mv^2

1/2*1*(3600cos^2 (60t) )

1/2*3600*cos^2 (30pi)

1800 units^2 /s

x=10sin(60t)

x=0

after pi/2 second it will be at

mean position

at mean position  potential energy =0

in many books it is assumed that

ke=total energy

but

ke+pe=total energy