Question

a body of mass 1 kg falls from rest through a distance of 200 m and acquires a spped of 50 m/s.workdone against friction of air is​

Answer 1

Answer:

the work done=force*displacement

force =mass*acceleration

mass=1kg

acceleration=g=9.8m/s^2

force=1*9.8=9.8N

displacement=200m

work done=9.8*200=1960J

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Answer 2

Answer:

given

Explanation:

mass is equal to 1 kg

displacement is equal to 200 metre

initial velocity is equal to zero

final velocity is equal to 50 metre per second

WORKDONE = force * displacement

force = mass * acceleration

F = 1 * 9.8

therefore , force = 9.8Newton

workdone = 9.8*200

workdone = 1960joule