a body of mass 1 kg is kept at rest a constant force of 6 Newton start acting on it find the time taken by the body to move through a distance of 12m
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acceleration produced by 6 N= 6/1 =6ms^-2
distance to be travelled =12m
using Newton's 2nd law of motion,
s = ut + at^2/2 where,
u=0 ,a=6,s=12
6*t*t/2 =12
3*t*t=12
t^2 =4
t= 2sec
distance to be travelled =12m
using Newton's 2nd law of motion,
s = ut + at^2/2 where,
u=0 ,a=6,s=12
6*t*t/2 =12
3*t*t=12
t^2 =4
t= 2sec
anshika885:
thnke
Answered by
2
HEYA!!
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✨Given that
Mass : 1 kg
Force : 6 N .
Acceleration :
Using the formula
F =ma
6 = 1 × A
Acceleration = 6ms-2.
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Now ,
Initial velocity u =0 { body is at rest }
Distance s = 12 m .
Time taken = ?
Using second equation of motion ,
12 = 0 × t + 1/2 × 6 × (t)^2
12 = 3 t^2
3 t^2 = 12
t^2 =4
T = 2 seconds .
--------------------------------------------------------------------------------------------------
----------
-----------------------------------------------------------------------------------------------------
✨Given that
Mass : 1 kg
Force : 6 N .
Acceleration :
Using the formula
F =ma
6 = 1 × A
Acceleration = 6ms-2.
----------------------------------------------------
---------------------------------------------------
Now ,
Initial velocity u =0 { body is at rest }
Distance s = 12 m .
Time taken = ?
Using second equation of motion ,
12 = 0 × t + 1/2 × 6 × (t)^2
12 = 3 t^2
3 t^2 = 12
t^2 =4
T = 2 seconds .
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