Question

A body of mass 1 kg is made to oscillate on a
spring of force constant 16 N/m. Calculate -
Angular Frequency.​

Answer 1

Answer:

We have,

m=1 kg, K=16 N/m

ω=

m

K

for a S.H.M

=

1

16

=4 rad/s

Also,

ω=2πn⇒n=

2π

ω

=

2π

4

=

π

2

Hz.

∴n=

3.14

2

=0.6369 Hz.

The angular frequency of the body is 4rad/s and the frequency of vibration is 0.6369 Hz.

Hence, this is the answer.

Answer 2

✍︎ANSWER✍︎

ᴡᴇ ʜᴀᴠᴇ,

ᴍ=1 ᴋɢ, ᴋ=16 ɴ/ᴍ

$w = \sqrt{ \frac{k}{m} }$

➪

$\sqrt{ \frac{16}{1} } = 4 \: \frac{rad}{s}$

ᴀʟsᴏ, 

ω=2πɴ⇒ɴ= w/ 2πω= 4/2π = 2/ π ʜᴢ.

∴ɴ= 2/ 3.142=0.6369 ʜᴢ.

ᴛʜᴇ ᴀɴɢᴜʟᴀʀ ғʀᴇǫᴜᴇɴᴄʏ ᴏғ ᴛʜᴇ ʙᴏᴅʏ ɪs 4ʀᴀᴅ/s ᴀɴᴅ ᴛʜᴇ ғʀᴇǫᴜᴇɴᴄʏ ᴏғ ᴠɪʙʀᴀᴛɪᴏɴ ɪs 0.6369 ʜᴢ.

ʜᴇɴᴄᴇ, ᴛʜɪs ɪs ᴛʜᴇ ᴀɴsᴡᴇʀ.

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