A body of mass 1 kg is revolved in a horizontal circle
by attaching to one end of 1 metre long string. If the
frequency of revolution is 20 rev/s, find about the
axis of rotation (i) moment of inertia, (ii) angular
momentum, (iii) rotational kinetic energy of the body
and (iv) centripetal force acting on the body.
Ans. (i) 1 kg mº, (ii) 40 a kg m? s?, (iii) 800 J,
(iv) 1600 N.
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Answer:
Tension in the string
T = mv²/R
T = Rω²
T = 0.1 × (3)²
T = 0.1(9)
T = 0.9 N
linear velocity
V = Rω
V = 0.1(3)
V = 0.3 m/s
linear acceleration
a = v²/R
a = (0.3)²/0.1
a = 0.9 m/s²
angular acceleration
α = a/R
α = 0.9/0.1
α = 9 rad/s²
Answered by
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Tension in the string
T = mv²/R
T = Rω²
T = 0.1 × (3)²
T = 0.1(9)
T = 0.9 N
linear velocity
V = Rω
V = 0.1(3)
V = 0.3 m/s
linear acceleration
a = v²/R
a = (0.3)²/0.1
a = 0.9 m/s²
angular acceleration
α = a/R
α = 0.9/0.1
α = 9 rad/s²
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