Physics, asked by Anbu11, 1 year ago

A body of mass 1 kg is thrown upwards with velocity of 10m/s comes to rest ( momentarily) after moving up 4m. What is the work done by air drag in this process.





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Answers

Answered by pankaj72
2
1000/10=100
so work done =100 multiple 4=400

Anbu11: wrong
Anbu11: the answer given is -10J
zakas: hey your answer is wrong
Answered by zakas
1
work = force × displacement
we have to calculate force then we need acceleration for acceleration we use the third kinematics equation which is

 {v }^{2}  =  {u}^{2}  + 2as
here v is final velocity
u is initial velocity
a is acceleration
s is distance travelled
keeping the value in the formula we got acceleration is equals 12.5m/S2

force is equals mass into acceleration then the masses 1 kg acceleration is equal to 12.5
force is 12.5kg m/S2


zakas: force = 12.5 then work = force × displacement 12.5×4 =50J the answer is 50 joule work done
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