Question

. A body of mass 1 kg is tied to a string and revolved in a horizonta
circle of radius 1 m. Calculate the maximum number of revolution
is per minute so that the string does not break. The breaking tensior
of the string is 9.86​

Answer 1

$\huge\underline\orange{\mathcal Answer}$

$\large\blue{\boxed{\mathcal 30 r.p.m}}$

$\huge\underline\orange{\mathcal Solution}$

Given :-

Mass(m) = 1 kg

Radius (r)= 1m

Force (F) = 9.86 N

We know that :-

$\large{\boxed{\mathcal F = mr{w}^{2}}}$

$\large{\mathcal {w}^{2}= {\frac{F}{mr}}}$

$\large{\mathcal w ={\sqrt{\frac{F}{mr}}}}$

$\large{\mathcal w = {\sqrt{\frac{9.86}{1×1}}}}$

$\large{\mathcal w = 3.14 r/s}$

Now, the number of resolution per minute

$\huge{\boxed{\mathcal w={\frac{2πN}{60}}}}$

$\large{\mathcal N={\frac{60×3.14}{2×3.14}}}$

$\huge{\boxed{\mathcal N = 30 r.p.m}}$

Hence, the maximum number of resolution per minute is 30 r.p.m