A body of mass 1 kg moves along +ve x-axis with velocity 3 ms and a constant force of 4N exerted
on it along y-axis. Find position vector of body after 1 sec.
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Answer:7m
Explanation:velocity=3i
From foce j
F=mdv/dt
4=1*dv/1sec
V=4j
Resultent velocity 3i+4j
=5m/s
Distance =velocity*time+1/2atsquar
Dst=7m
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