Question

A body of mass 1 kg moves along +ve x-axis with velocity 3 ms and a constant force of 4N exerted
on it along y-axis. Find position vector of body after 1 sec.​

Answer 1

Answer:7m

Explanation:velocity=3i

From foce j

F=mdv/dt

4=1*dv/1sec

V=4j

Resultent velocity 3i+4j

=5m/s

Distance =velocity*time+1/2atsquar

Dst=7m