Question

A body of mass 1 kg moving with velocity 1 m/s makes an
elastic one dimensional collision with an identical stationary body. they are in contact for a brief period 1s. their force of. interaction increases from zero to F0 linearly in 0.5s and decreases linearly to zero in a further 0.5s as shown in figure. find the magnitude of F0 in newtons.​

Answer 1

SóluTion :-

In the one dimensional elastic collision with one body at rest, the body moving initially comes to rest & the on which was at rest earlier starts moving the velocity that first body had before collision.

$\sf {So,\ if\ m\ and\ V_0\ be\ the\ mass\ and\ velocity\ of\ body,}$

$\sf {the\ change\ in\ momentum }$

$\sf {= mV_0 \implies \int\ Fdt=mV_0}\\\\\\sf {\implies \int\ Fdt=mV_0 \implies F = \frac{2mV_0}{\Delta t } = 2N}$

$\rule {130}{2}\ Be\ Brainly\ \star$

Answer 2

plz refer to the attachment

✌✌HOPE IT HELPS YOU ✌✌

PLZ MARK AS BRAINLIEST...