Question

A body of mass 10 kg at rest explodes

into 3 parts having masses in the ratio
2:2:1. The parts with equal masses
scattering mutually perpendicular
directions with speed 10 ms. What will
be the velocity of lighter segment?
(Please answer clearly)

Answer 1

Answer:

we know it divided into equal parts

so let no be x

then 2x + 2x + x =10

5x = 10

x = 2

all are have velocity 10 m/s

so the velocity of lighter segment is

10×2=20 m/s as a momentum