Question

A body of mass 10 kg at rest is acted upon simultaneously by two forces 4N and 3N at right angles to each other. The kinetic energy of body at end of 10sec is

Answer 1

Heya mate,

here is your answer,
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Since it is acted upon simultaneously by two forces 4N and 3N at right angles,
$net \: force = \sqrt{ {4}^{2} + {3}^{2} } = 5n$
The mass is given as 10 Kg --- a = F/m = 5/10 = 0.5 m/s^2

Now we can calculate the kinetic energy as K.E =
$\frac{1}{2} m {v}^{2} = \frac{1}{2} m {(at)}^{2}$
==> KE =
$\frac{1}{2} \times 10 \times {0.5}^{2} \times 10s = 125 \: j$
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# nikzz

Hope u like it ☺☺

Answer 2

Answer:

this is the answer

I hope it's helps