A body of mass 10 kg is lifted to height 10 m . Calcute the potential energy if this body is allowed to fall . Find the kinetic energy before it touches the ground . ( g = 10 m\s )
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Answered by
1
P.E = mgh
=10*10*10
=1000 J -----at the top
K.E = 1/2mv²
at the ground P.E = 0
therefore K.E =1000 J ( by conservation of energy )
I HOPE IT HELPS...........
=10*10*10
=1000 J -----at the top
K.E = 1/2mv²
at the ground P.E = 0
therefore K.E =1000 J ( by conservation of energy )
I HOPE IT HELPS...........
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Answered by
1
P.E.=mgh=10×10×10
=1000J
K.E.=1/2mv^2=1/2×10×(10)^2
=5×100
=500
=1000J
K.E.=1/2mv^2=1/2×10×(10)^2
=5×100
=500
v = 10m/s how ?
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