A body of mass 10 kg is on a rough horizontal surface .if the coefficient of kinetic friction between surface in contact is 0.3, the force which can keep it in uniform velocity is ?
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Force of friction =mass *coefficient*gravitation
Ff=10Kg*0.3*10m/s^2
Ff=30N
Ff=10Kg*0.3*10m/s^2
Ff=30N
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Answer:
f= mu R
f = 0.3× mg
= 0.3× 10× 9.8
= 98× 0.3
= 29.4N
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