A body of mass 10 kg is placed on an inclined surface of angle 30 if the coefficient of friction is 1÷3^1÷2 fid the force required to just push the body up the inclined plane the forxe being applied parallel to the inclined surface
Answers
Assuming the surface is flat, having no inclination.
Minimum Force (F) required to move the block= ¥N in horizontal direction
Where, ¥ is coffecient of friction
N is normal force which is equal to mg in this case, here m is mass of body and g is value of acceleration due to gravity.
So, F = ¥N = ¥mg = 0.2 × 3 × 9.8 = 5.88 Newton
Answer:
Explanation:
Angle of repose is simply the angle of inclination for which friction is max. i.e. u=tan(theta). If angle of inclination is less than the max. angle then friction will b more as tan theta has nw bcm small due to smaller angle, if angle of inclination is more than the theta for max friction then the block will slide down as friction wont b enogh to stop that block. In ur qstion its said that block has to b pushed down so angle of inclination is less than the angle or thetafor max. friction do option C is correct. Its kind of messy wht i wrote but read it twice or more n also frm ur physics book or notes u ll get it. Its very simple.Hope it helps!!