a body of mass 10 kg is pushed throug a distance of 5 metre across the floor with constant speed if the friction force attract by the by the floor is 25 Newton find work done by the frictional force
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As the frictional force is acting opposite to the direction of the motion of the block, it is making an angle of 180 degree..
s= 5 metre
Work done, W = F.s.cosθ
= 25×5× cos180
= -125 (cos180= -1)
HENCE the work done is -125 J
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Answer:
Here the answer is - 125
work done = F.s costheta
cos teta = 180°=-1
25×5×-1 = -125J
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